In fig ps/sq pt/tr
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In fig ps/sq pt/tr
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WebIn figure, two line segments AC and BD intersect each other at the point P such that PA = 6 cm, PB = 3 cm, PC = 2.5 cm, PD = 5 cm, ∠APB = 50° and ∠CDP = 30°. Then, ∠PBA is equal to (a) 50° (b) 30° (c) 60° (d) 100° Solution: (d) 100° Explanation: From ∆APB and ∆CPD, ∠APB = ∠CPD = 50° (since they are vertically opposite angles) AP/PD = 6/5 … (i) WebIn the figure shown below , if P S SQ = P T T R and ∠ PST= ∠ PRQ, then Δ PQR is a/an triangle. Q. In below shown figure, P S SQ = P T T R and ∠ PST= ∠ PRQ. Then Δ PQR is an isosceles Triangle. Q. In the given figure, P S SQ = P T T R and ∠ PST= ∠ PRQ, then Δ PQR is _______triangle. Q.
WebFeb 21, 2024 · In figure, PS/SQ = PT/TR and ∠PST = ∠PRQ. Prove that ΔPQR is isosceles triangle. Solve with complete steps and reasoning. WebOct 2, 2024 · In the given figure, in a triangle PQR, ST QR and PS / SQ = 3 / 5 and PR = 28 cm, find PT. triangles cbse class-10 1 Answer +1 vote answered Oct 2, 2024 by Supria (64.2k points) selected Oct 3, 2024 by faiz Best answer According to the question, ← Prev Question Next Question → Find MCQs & Mock Test JEE Main 2024 Test Series NEET Test Series
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WebFeb 25, 2024 · In fig., PS = 2, SQ = 6, QR = 5, PT = x and TR = y. Then find the pair of value of x and y such that ST II side QR.
WebMar 29, 2024 · Transcript. Example 3 In figure , / = / and PST = PRQ. Prove that PQR is an isosceles triangle. Given: / = / PST = PRQ To prove: PQR is an isosceles triangles Proof: … maryland class 4 limited winery licenseWebApr 27, 2024 · In Fig., S and T are points on the sides PQ and PR respectively of A PQR such that PT = 2 cm, TR = 4 cm and ST is parallel to QR. Find the ratio of the areas of PST and PQR. triangles class-10 1 Answer +1 vote answered Apr 27, 2024 by Amishi (30.3k points) selected Apr 28, 2024 by Saadah Best answer Given ST QR, TR = 4 cm and PT = 2 cm. So, hurtmore chase godalmingWebAug 26, 2024 · PS/SQ = PT/TR ⇒ ST QR By converse of basic proportionality theorem, If a line is drawn parallel to one side of a triangle to intersect the other sides in distinct points, the other two sides are divided in the same ratio. ∴ ∠1 = PQR And ∠2 = ∠PRQ In ∆PTS and ∆PRQ. ∠P = ∠P [Common angles] ∠1 = ∠PQR (proved) ∠2 = ∠PRQ (proved) ∴ ∆PTS – ∆PRQ hurtmore golf bookingWebSolution The correct option is A an Isosceles It is given that P S SQ = P T T R By converse of Basic Proportionality Theorem (BPT), ST QR ∴, ∠PST=∠PQR .......... (Corresponding … maryland claim form st-912WebIn the given fig, ST QR, PS = 2 cm and SQ = 3 cm. What is the ratio of the area of ∆PQR to the area of ∆PST? from Mathematics Triangles Class 10 CBSE Triangles Advertisement … hurtmore golf club reviewWebJul 30, 2024 · In Fig. PS/SQ = PT/TR and ∠ PST = ∠ PRQ. Prove that PQR is an isosceles triangle. Triangles 10th - YouTube Class-10 Maths Chapter-6, TrianglesExample No- 3In … maryland cjis manualWebOct 11, 2024 · PS / SQ = PT /TR. The figure that has it's ratio equal is the figure that the lines ST and QR are parallel. Checking the first figure gives = PS / SQ = 7.5 / 17.5 = 0.428571. Also = PT /TR = 8.7 / 20.3 = 0.428571. since the ratio is equal the two lines are parallel in the . maryland cjis fingerprinting